Well it isn't. I'm trying to prove it. So I assume there is more than one sylow-3 subgroup, each has order 9, we have 4 of them, now their intersection is either e or has order 3. if it is e, then we have 32 elements in these subgroups besides e (33rd) then assume we have more than one sylow-2 subgroup, we should have 3, but then their intersection has order 1, or 2. So now it works for all cases except when the intersection of the sylow 3 subgroups is 3 and that of the sylow 2-subgrps is 1, then I get the magic number 36. What should I be looking for in this proof. I was advised there is a way to prove it using this way without the appeal to homomorphisms to Sn.