• Support PF! Buy your school textbooks, materials and every day products Here!

A hand on this one will be great i=1/L∫Vdt|| V=(6t+26)/(t^2+10t+21).

  • Thread starter cunhasb
  • Start date
  • #1
12
0
I hope anyone could give me a hand on this one...

The induced emf in a 5-henry inductor varies as V=(6t+26)/(t^2+10t+21). Recalling that current i=1/L∫Vdt, find the formula for the current i as a function of time t.

This is what I've gotten so far...

∫(6t+26)/(t^2+10t+21)=(6t+26)/(t+3)(t+7)=A/(t+3)+B(t+7)=2/(t+3)+4/(t+7) dt

i=1/5∫2/(t+3)+4/(t+7)dt
i=1/5(ln(t+3)^2+ln(t+7)^4+k...

Well should I stop here since I've gotten only the variable t on the right side of the formula or should differentiate it since they are asking for the formula of currentas a function of time t? If so... is this correct?

di/dt=1/5{[(2t+6)/(t+3)^2]+[(4t+28)/(t+7)^4)]}

Thank you again guys...
 

Answers and Replies

  • #2
HallsofIvy
Science Advisor
Homework Helper
41,770
911
You want i as a function of time, and that is what you have!

There is no reason to differentiate it- remember that integration and differentation are "opposites" differentiating now would just return you to the function you integrated!

(What happened to 1/L? Shouldn't that be in there?)
 
  • #3
12
0
So the answer will be i=1/5(ln(t+3)^2+ln(t+7)^4+k...

now about the 1/L this is the 1/5 (I had 5-henry inductor)...
Is it right?
 

Related Threads for: A hand on this one will be great i=1/L∫Vdt|| V=(6t+26)/(t^2+10t+21).

  • Last Post
Replies
1
Views
2K
Replies
3
Views
6K
  • Last Post
Replies
1
Views
878
  • Last Post
Replies
6
Views
5K
  • Last Post
Replies
16
Views
3K
Replies
3
Views
2K
Top