1. The problem statement, all variables and given/known data A heavy-duty stapling gun uses a 0.151-kg metal rod that rams against the staple to eject it. The rod is pushed by a stiff spring called a "ram spring" (k = 35007 N/m). The mass of this spring may be ignored. Squeezing the handle of the gun first compresses the ram spring by 3.9 multiplied by 10-2m from its unstrained length and then releases it. Assuming that the ram spring is oriented vertically and is still compressed by 1.0 multiplied by 10-2m when the downward-moving ram hits the staple, find the speed of the ram at the instant of contact. 2. Relevant equations U=(1/2)kx^2 (1/2)kx^2=(1/2)mv^2 3. The attempt at a solution I have no idea what to do. My answer was 13.96 m/s but it was wrong.