1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

A hiker begins a trip by first walking 25.0 km southeast from camp. On the second day

  1. Aug 25, 2010 #1
    A hiker begins a trip by first walking 25.0 km southeast from camp. On the second day she walks 40.0 km in a direction 60.0 north of east, at which point she discovers a forest ranger's tower.

    my answer is :

    Ax = A cos (60 )

    R= A+B = 25 + 40 = 65

    thanks
     
  2. jcsd
  3. Aug 25, 2010 #2

    Mark44

    Staff: Mentor

    Re: A hiker begins a trip by first walking 25.0 km southeast from camp. On the second

    What is the question?
     
  4. Aug 25, 2010 #3

    eumyang

    User Avatar
    Homework Helper

    Re: A hiker begins a trip by first walking 25.0 km southeast from camp. On the second

    Usually questions like these ask the distance from the beginning point to the ending point, and the bearing. Though the work the OP given doesn't make sense. Let the camp be point C, let the spot where the hiker rested after the 1st day be point R, and let the tower be point T.

    You have a triangle. Sides CR and RT are known, plus angle R (you need to figure the angle out based on the information given). Use the Law of Cosines to find side CT (the distance from the camp to the tower). Use either the Law of Cosines or the Law of Sines to find angle C.

    Now, angle C is NOT the bearing. You'll need to look at a diagram and figure out how to get the bearing of the tower from the camp. If anything is unclear, post a diagram, and we'll try to clarify.


    69
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: A hiker begins a trip by first walking 25.0 km southeast from camp. On the second day
Loading...