A hot air balloon has just lifted off and is rising at the constant

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SUMMARY

A hot air balloon rises at a constant rate of 1.6 m/s while a camera is tossed upward with an initial speed of 10.8 m/s from a position 2.5 m below the balloon. To determine the height of the balloon when the camera reaches it, one must apply kinematic equations for one-dimensional motion, taking into account the constant acceleration due to gravity. The final positions of both the balloon and the camera can be set equal to solve for the height at which they meet.

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Homework Statement


A hot air balloon has just lifted off and is rising at the constant rate of 1.6 m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 10.8 m/s. If the passenger is 2.5 m above her friend when the camera is tossed, how high is she when the camera reaches her?

Homework Equations


i tried using constant acceleration equations but they made no sense :(

The Attempt at a Solution


its 2.8 something... but i just really want to know how to set up the problem!
Thanks
 
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Since you have a constant acceleration due to gravity for the camera, a known initial velocity both objects, and a known initial position (of 0 for the camera and 2.5m for the balloon) and all of your motion is in the same dimension (vertical), you can set use the kinematic equations for one-dimensional motion to find out what height the camera reaches the gal in the balloon.

(Try setting the final position of the camera & the balloon equal to each other, which will let you set the equations for the different objects equal to each other.)
 

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