- #1
strugglin-physics
- 47
- 0
A force of 21.2 N is required to start a 6.65 kg box moving across a horizontal concrete floor. What is the coefficient of static friction between the box and the floor?
I've drawn my free body diagram and found that the y motion is N^F,B-W^E,B=0 I also know that the Force is larger than the friction
21.2 N - friction = 6.65a acceleration is not zero in this case right cause if it were zero than the friction would be 21.2
I've drawn my free body diagram and found that the y motion is N^F,B-W^E,B=0 I also know that the Force is larger than the friction
21.2 N - friction = 6.65a acceleration is not zero in this case right cause if it were zero than the friction would be 21.2