- #1

carlo

- 7

- 0

Hi to everybody;

I wanted to ask: which is the factor of conversion from cm^{-1} to eV?

Thank you!

I wanted to ask: which is the factor of conversion from cm^{-1} to eV?

Thank you!

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter carlo
- Start date

- #1

carlo

- 7

- 0

Hi to everybody;

I wanted to ask: which is the factor of conversion from cm^{-1} to eV?

Thank you!

I wanted to ask: which is the factor of conversion from cm^{-1} to eV?

Thank you!

- #2

- 35,995

- 4,714

Hi to everybody;

I wanted to ask: which is the factor of conversion from cm^{-1} to eV?

Thank you!

I'll ask this first so that you know where to look. Do you have Ashcroft and Mermin's "Solid State Physics" text? It is listed in the table on the inside back cover of the book.

Zz.

- #3

carlo

- 7

- 0

not here

thanks

thanks

- #4

pam

- 458

- 1

A number I use is that 1=1.932 keV-Angstroms.

- #5

HallsofIvy

Science Advisor

Homework Helper

- 43,021

- 970

- #6

- 35,995

- 4,714

In optical conductivity area of study, it is very common to talk in inverse length to signify a corresponding energy scale. This is because from experiment, the value of "k" (either crystal momentum, electronic momentum, or wave number) falls out naturally from measurement.

Zz.

- #7

- 35,995

- 4,714

[itex]1 eV = 8.065 \times 10^3 cm^{-1}[/itex]

Zz.

- #8

pam

- 458

- 1

That is because mine is for k=1/lambda, with k in cm^-1,

and AM is for p=2pi/lambda with p in cm^-1.

You have to decide whether you are using k or p.

Share:

- Replies
- 8

- Views
- 842

- Replies
- 5

- Views
- 156

- Replies
- 5

- Views
- 908

- Replies
- 38

- Views
- 2K

- Last Post

- Replies
- 0

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 706

- Last Post

- Replies
- 5

- Views
- 9K

- Last Post

- Replies
- 5

- Views
- 13K

- Last Post

- Replies
- 2

- Views
- 985

- Replies
- 0

- Views
- 8K