- #1

mratwi36

- 8

- 0

**a little help pleasezz**

http://i21.photobucket.com/albums/b283/NMchugh/Various/vectors.png

i'd like just some confirmation on my answers and thanks alot.the link is the question.

well calling AB=T1, BC=T2 and BD=T3

recommend splitting vectors into components and equating them...

Vertical Component of T1 = T1*sin60 = weight of mass = 40*9.8=392N therefore T1 = 452.6N

now T2 = horizontal components of T1 & T3 = (T3*4/5)+(T1*Cos60)

now Vert. comp. T3 = T3*3/5 = Vert. comp. T1 = weight of mass =392N (from first line)

therefore T3=653.3N

now substitute T3 = 635.3N and T1 = 452.6N into the equation for T2 above and you find T2=748

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