- #1
mratwi36
- 8
- 0
a little help pleasezz
http://i21.photobucket.com/albums/b283/NMchugh/Various/vectors.png
i'd like just some confirmation on my answers and thanks alot.the link is the question.
well calling AB=T1, BC=T2 and BD=T3
recommend splitting vectors into components and equating them...
Vertical Component of T1 = T1*sin60 = weight of mass = 40*9.8=392N therefore T1 = 452.6N
now T2 = horizontal components of T1 & T3 = (T3*4/5)+(T1*Cos60)
now Vert. comp. T3 = T3*3/5 = Vert. comp. T1 = weight of mass =392N (from first line)
therefore T3=653.3N
now substitute T3 = 635.3N and T1 = 452.6N into the equation for T2 above and you find T2=748
http://i21.photobucket.com/albums/b283/NMchugh/Various/vectors.png
i'd like just some confirmation on my answers and thanks alot.the link is the question.
well calling AB=T1, BC=T2 and BD=T3
recommend splitting vectors into components and equating them...
Vertical Component of T1 = T1*sin60 = weight of mass = 40*9.8=392N therefore T1 = 452.6N
now T2 = horizontal components of T1 & T3 = (T3*4/5)+(T1*Cos60)
now Vert. comp. T3 = T3*3/5 = Vert. comp. T1 = weight of mass =392N (from first line)
therefore T3=653.3N
now substitute T3 = 635.3N and T1 = 452.6N into the equation for T2 above and you find T2=748
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