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A little integration problem.

  1. Apr 15, 2009 #1

    Noo

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    Solved. Thanks.
     
    Last edited: Apr 15, 2009
  2. jcsd
  3. Apr 15, 2009 #2
    The simplest way to solve that indefinite integral is to realize that

    [tex]\frac{d}{dx}tan x = sec^{2}x[/tex] , and try a u-substitution from there...
     
  4. Apr 15, 2009 #3

    Noo

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    Yes, sorry, i am stupid. I realised that 2 minutes after posting here. I'm pretty sure i have it now. It's just -(2+u)^{-1} for u=tanx, right? And thanks for the reply.
     
  5. Apr 15, 2009 #4
    No problem. And, actually, you can set u = tan(x) + 2 to make things even easier. 2 is just a constant, so the derivative of tan(x) is the same as the derivative of tan(x) + 2.
     
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