• Support PF! Buy your school textbooks, materials and every day products Here!

A little integration problem.

  • Thread starter Noo
  • Start date
  • #1
Noo
26
0
Solved. Thanks.
 
Last edited:

Answers and Replies

  • #2
29
0
The simplest way to solve that indefinite integral is to realize that

[tex]\frac{d}{dx}tan x = sec^{2}x[/tex] , and try a u-substitution from there...
 
  • #3
Noo
26
0
The simplest way to solve that indefinite integral is to realize that

[tex]\frac{d}{dx}tan x = sec^{2}x[/tex] , and try a u-substitution from there...
Yes, sorry, i am stupid. I realised that 2 minutes after posting here. I'm pretty sure i have it now. It's just -(2+u)^{-1} for u=tanx, right? And thanks for the reply.
 
  • #4
29
0
It's just -(2+u)^{-1} for u=tanx, right? And thanks for the reply.
No problem. And, actually, you can set u = tan(x) + 2 to make things even easier. 2 is just a constant, so the derivative of tan(x) is the same as the derivative of tan(x) + 2.
 

Related Threads for: A little integration problem.

  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
0
Views
1K
Replies
5
Views
1K
Replies
15
Views
3K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
5
Views
2K
Replies
6
Views
2K
Top