- #1

- 26

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Solved. Thanks.

Last edited:

- Thread starter Noo
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- #1

- 26

- 0

Solved. Thanks.

Last edited:

- #2

- 29

- 0

[tex]\frac{d}{dx}tan x = sec^{2}x[/tex] , and try a u-substitution from there...

- #3

- 26

- 0

Yes, sorry, i am stupid. I realised that 2 minutes after posting here. I'm pretty sure i have it now. It's just -(2+u)^{-1} for u=tanx, right? And thanks for the reply.

[tex]\frac{d}{dx}tan x = sec^{2}x[/tex] , and try a u-substitution from there...

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