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A little problem

  1. May 25, 2005 #1
    Here is the question: "could you fine n>2 (n natural number) so that: a^n+ b^n=c^n with a, b and c real numbers".

    I have got an idea but I am not sure if it works.

    Thank you very much

  2. jcsd
  3. May 25, 2005 #2
    Sure, no problem. Take n = 3 and a = 1, b = 2 and c = 3^(2/3)...
  4. May 25, 2005 #3

    There are none for integers a,b, and c.
  5. May 25, 2005 #4
    yep it is fermat's theorem...ok thank you!
  6. May 25, 2005 #5


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    But what you posted isn't Fermat's Last Theorem. For real a,b and c, there are an infinite number of solutions for every natural number value of n.
  7. May 25, 2005 #6
    He just neglected to mention the integer requirement, which I amended.
  8. May 25, 2005 #7


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    No he didn't neglect anything, he said "with a, b and c real numbers".
  9. May 25, 2005 #8
    How is that not neglecting to mention the integer requirement.
  10. May 25, 2005 #9


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    The Real Number set is an entirely different number set to the Integers. The poster said Real Numbers.
  11. May 25, 2005 #10
    The issue here is of word choice. I said "neglecting to mention the integer requirement" is the same as "not mentioning the integer requirement".

    He mentioned a problem very similar to FLT in which I referenced him to the correct form. It turns out that is what he is looking for.
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