::A mail bag with a mass of 105 kg is suspended by a vertical rope of length 7.00 m . A) What horizontal force is necessary to hold the bag in a position displaced sideways a distance 3.00 m from its initial position? Take free fall acceleration to be g = 9.80 m/s2 . B) How much work is done by the worker in moving the bag to this position? Take free fall acceleration to be g = 9.80 m/s2 . m= 105 kg y= 7 m x= 3 m So first I made a right triangle to find the angles, the angles I found were 25(from the vertical) and 66. The tension in the string is 105 kg x 9.8 m/s2 right? with that I have T=1029 N I then used 1029tan(25)= 479 N . What do I need to do to figure out ho much work is done? tips for moving on?