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::A mail bag with a mass of 105 kg is suspended by a vertical rope of length 7.00 m .

A) What horizontal force is necessary to hold the bag in a position displaced sideways a distance 3.00 m from its initial position?

Take free fall acceleration to be g = 9.80 m/s

B) How much work is done by the worker in moving the bag to this position?

Take free fall acceleration to be g = 9.80 m/s

m= 105 kg

y= 7 m

x= 3 m

So first I made a right triangle to find the angles, the angles I found were 25(from the vertical) and 66.

The tension in the string is 105 kg x 9.8 m/s

I then used 1029tan(25)= 479 N .

What do I need to do to figure out ho much work is done?

tips for moving on?

A) What horizontal force is necessary to hold the bag in a position displaced sideways a distance 3.00 m from its initial position?

Take free fall acceleration to be g = 9.80 m/s

^{2}.B) How much work is done by the worker in moving the bag to this position?

Take free fall acceleration to be g = 9.80 m/s

^{2}.m= 105 kg

y= 7 m

x= 3 m

So first I made a right triangle to find the angles, the angles I found were 25(from the vertical) and 66.

The tension in the string is 105 kg x 9.8 m/s

^{2}right? with that I have T=1029 NI then used 1029tan(25)= 479 N .

What do I need to do to figure out ho much work is done?

tips for moving on?

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