(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The figure shows an 7.9 kg stone at rest on a spring. The spring is compressed 10 cm by the stone. The stone is then pushed down an additional 32 cm and released. To what maximum height (in cm) does the stone rise from that position?

2. Relevant equations

k = mg/d

v = sqrt((kx^2)/m)

h = ((1/2)(v^2))/(g)

3. The attempt at a solution

So this is what I've tried:

k = mg/d

k = (7.9)(9.8) / (.1)

k = 774.2 N/m

v = sqrt((kx^2)/m)

v = sqrt((774.2*.32^2)/(7.9))

v = sqrt(79.27808/7.9)

v = 3.1678

h = (1/2v^2) / (g)

h = (1/2)(10.0352) / (9.8)

h = .512m

h = 51.2cm

Does this seem correct? I only have one shot left on the wiley plus and don't want to risk it if it's wrong. Appreciate the help!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# A mass on a spring?

**Physics Forums | Science Articles, Homework Help, Discussion**