- #1
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Homework Statement
Attached
Homework Equations
kinetic energy = (1/2) m v^2
potential energy = mgh
The Attempt at a Solution
Did I do this correctly,
At the top, kinetic energy is 0 since it starts at rest. At the bottom we choose the potential to be zero
So using conservation,
[tex] mgz= \frac{1}{2}m\vec{v_f}^2[/tex]
Then, substitute [tex] z=s(t)sin\theta[/tex],
And [tex] \vec{v_f} = \vec{a}t [/tex]
where [tex] \vec{a} = \frac{\vec{F}}{m} = \frac{mgsin\theta}{m} = gsin\theta [/tex]
To get [tex] mgs(t)sin\theta = \frac{1}{2}m(gtsin\theta)^2 [/tex]
solve for [tex] s(t) = \frac{gt^2sin\theta}{2} [/tex]