- #1

eljose79

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- Mathematica
- Thread starter eljose79
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- #1

eljose79

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- #2

shchr

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Do you mean "propagators are Unitary"? I think a propagator is an operator which governs time evolution of an eigenstate. In order that total of probability obtained from the integration of the eigenstate's inner product remains 1 in the course of time evolution, time evolution operator should be Unitary. If so, I think propagators are Green's function used to solve a problem by perturbation method. So although a time evolution operator of an exact solution of the problem should be Unitary, propagators are not neccesarily Unitary, I think. Propagators are not the operators which should be diagonalized by eigenfunctions in order to solve the problem. I heard that S matrix which is constructed by a propagator is Unitary, though. How do you think about this.

- #3

jeff

Science Advisor

- 658

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Propagators are usually defined not as operators but as amplitudes for particles to be created at some given point and annhilated at another.

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- #4

shchr

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