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It is also possible to prove that a manifold is maximally symmetric if and only if the Riemann tensor obeys the relation

[tex] \displaystyle R_{abcd} = \frac{R}{n(n-1)} (g_{ac} g_{bd} - g_{ad} g_{bc}) \textrm{,} [/tex]

where [tex] g_{\mu \nu} [/tex] is the metric and [tex] R [/tex] is the curvature scalar.

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apeiron

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Does this mean a flat Euclidean space is more symmetric than spaces with closed and open curvature (hyperspheric and hyperbolic)?

And second, does this relate to an axis of scale symmetry? I mean a euclidean space looks the same (homogenous) on any scale, whereas step back far enough, and a hypersphere reveals its closed loop paths, a hyperbolic space reveals its divergences.

This would seem to be a third kind of invariance as it is not about translations or rotations but the self-similarity of geometric expansions and contractions.

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It depends on what you mean by "symmetry." Generally, in this context, a "symmetry" is taken to be an isometry of the metric, i.e., a diffeomorphism which pulls back the metric to itself. If this is taken as the definition, then, as I said above, all maximally symmetric spaces share the same number of symmetries. This includes the maximally symmetric spaces of both closed and open varieties, i.e., hyperboloids and hyperspheres (in general relativity, the analogous spaces are the de Sitter and anti-de Sitter cosmologies).Does this mean a flat Euclidean space is more symmetric than spaces with closed and open curvature (hyperspheric and hyperbolic)?

However, if you also include changes of scale in the definition of symmetry, the answer is different. A "change of scale" of the type you have described is usually called a conformal mapping; more precisely, two metrics [tex] g [/tex] and [tex] \tilde{g} [/tex] are conformally related if there exists a (nonvanishing, smooth) function [tex] \omega [/tex] of the coordinate functions such that [tex] \tilde{g} = \omega^2 g [/tex]. The idea of "symmetry under changes of scale" can then be articulated in terms of the existence of a diffeomorphism [tex] \varphi : M \to M [/tex] (where [tex] M [/tex] is the manifold) such that [tex] \varphi^{*} g [/tex] (i.e., the pullback of the metric by [tex] \varphi [/tex]) is conformally related to [tex] g [/tex]. Thus, a space is said to have a

Another way to phrase this is in terms of Killing fields. You may be familiar with ordinary Killing vector fields, which are defined as the generators of isometries and obey the equation [tex] \mathcal{L}_K g = 0 [/tex], where [tex] K [/tex] is the Killing field (i.e., [tex] K [/tex] Lie-transports the metric [tex] g [/tex]). In coordinates, this reduces to [tex] \nabla_{(a} K_{b)} = 0 [/tex]. Similarly, a

[tex]

\nabla_{(a} V_{b)} = \frac{2}{n} (\nabla^c V_c) g_{ab} \textrm{,}

[/tex]

which is called the

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apeiron

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Thanks for a quick introduction to the jargon in this area.Thus, in addition to a full complement of ordinary Killing vectors, Euclidean space is also blessed with a maximal collection ofconformalKilling vectors, making it "uber-maximally symmetric," unlike hyperspheres and hyperboloids. So, indeed, there is a "third kind of invariance," as you say, having to do with changes of scale, that Euclidean space possesses but other so-called maximally symmetric spaces do not.

It seems significant that flat euclidean geometry is picked out in this regard.

Noether would say for every symmetry there is an inertia or conservation law, so what is law that results from scale symmetry?

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There are a few problems with attempting to invoke Noether's Theorem to produce a symmetry from conformal Killing vectors. First, in order for Noether's Theorem to apply, you need a differentiable symmetry of anNoether would say for every symmetry there is an inertia or conservation law, so what is law that results from scale symmetry?

[tex]

I = \frac{1}{2} \int g_{ab} \frac{dx^a}{d\tau} \frac{dx^b}{d\tau} \textrm{.}

[/tex]

Furthermore, the type of "symmetry" indicated by the existence of conformal Killing vectors isn't exactly a "symmetry" in the sense of Noether's Theorem, since the conformal Killing equation doesn't quite give the invariance of the metric that Noether's Theorem requires. Instead, a conformal symmetry is defined as a diffeomorphism which changes the metric, but only in a certain allowed fashion, i.e., [tex] \varphi^{*} g = \omega^2 g [/tex]. In order to apply Noether's Theorem, it is my (admittedly limited) understanding that you would need something like [tex] \varphi^{*} g = g [/tex], which defines an

Despite all this, the presence of conformal Killing vectors is in fact enough to guarantee that certain quantities will be conserved, but only for a very special class of paths, i.e., null geodesics. (Obviously, this only applies to Lorentzian manifolds. I have no idea whether or not you can use a conformal Killing vector to construct an invariant in an ordinary Riemannian setting.) First, note that for an ordinary Killing vector [tex] K^a [/tex], if [tex] T^b [/tex] denotes the tangent vector to a unit-speed geodesic, we have

[tex]

T^a \nabla_a (T^b K_b) = T^a T^b K_{b;a} + K_b T^a T \indices{^b_{;a}} = 0

[/tex]

(by Killing's equation and the geodesic equation). Thus, the quantity [tex] L = T^b K_b [/tex] is conserved along geodesics. This holds for all Riemannian or pseudo-Riemannian metrics, and gives rise to such classical laws as the conservation of momentum, energy, and angular momentum in flat space.

A similar calculation for conformal geodesics [tex] Y^b [/tex], using the equation I gave in the last post, gives

[tex]

T^a \nabla_a (T^b Y_b) = \frac{1}{n} (\nabla^c Y_c) T^a T_a \textrm{.}

[/tex]

Thus, [tex] L [/tex] is not conserved for conformal Killing fields. However, if [tex] T [/tex] is the tangent to a null geodesic, then [tex] T^a T_a = 0 [/tex], so [tex] L [/tex] is again conserved. I think this is about as close to a Noether current as you can get from a conformal Killing vector. I haven't seen this applied in any specific examples, so I can't at the moment describe in physical terms precisely what this indicates for null paths of interest. I'll get back to you if I have any flashes of inspiration.

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apeiron

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The physical relevance of the question is the problem of the flatness of the expanding universe. Usually it is taken that it is a surprise the universe is (asymptotically) flat rather than curved positively/negatively. This seems an unnaturally poised situation.

But the alternative view would be that flatness is instead the self-selecting outcome for some reason. Because it has the highest symmetry (having scale symmetry as well) it is the trough state, the equilibrium balance.

Putting it simply, the other noether symmetries are you can go left or right, spin clockwise or anticlockwise, and go backwards or forwards in time (a little questionable this one).

Then in a fractal realm, you would be free to shrink or expand. Go either direction in this sense with no change. An observer moving across scale would still look out and see the same world, the event would still have the same relationship to the context.

A light cone would seem to have this kind of "inertia", this smooth expansion in scale. The intensity of a force wanes with an inverse square law, but the total force is a conserved quantity. So there seems a connection there.

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