- #1

jessicaw

- 56

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[tex] \overline{B_n}[/tex] is the smallest closed subset containing [tex] B_n[/tex].

Note that

[tex]\cup_{i=1}^n \overline{A_i}[/tex] is a closed subset containing [tex] B_n[/tex].

Thus,

[tex] \overline{B_n}\supset \cup_{i=1}^n \overline{A_i}[/tex]Isn't the truth should be that

[tex] \overline{B_n}[/tex] is the smallest?

How come claim that

[tex]\cup_{i=1}^n \overline{A_i}[/tex] is even smaller?