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A mono-energetic alpha beam

  1. Mar 26, 2016 #1
    I calculated the scattered angle & the kinematic factors for both Al & Au to be

    Is what I did right?
    E (Alpha) = stopping power x depth
    = 250 x 0.5 = 125 keV
    As for the maximum & the minimum scattered energy i didn't know how?
  2. jcsd
  3. Mar 28, 2016 #2
    Any feedback would be appreciated, I'm really struggling.
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