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## Main Question or Discussion Point

My problem is this.

We have three javelin throwers A,B and C.

It is known that A defeats B with probability 60%, B defeats C with probability again 60% and A has the better of C with 70%.

What are the a-priori probabilities of A, B, C winning the 3-way contest ?

If in general we have

We have three javelin throwers A,B and C.

It is known that A defeats B with probability 60%, B defeats C with probability again 60% and A has the better of C with 70%.

What are the a-priori probabilities of A, B, C winning the 3-way contest ?

If in general we have

**N**participants and**Pij**for the head to head probabilities, what is the formula for the win probability of each (**Qi = some f(Pij)**) ?