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I found a quick formula for calculate perfect numbers.

T(v)={{[1+sqrt(1+8*T(v-1))]*[1+sqrt(1+8*T(k))]}^2}/128 - {[1+sqrt(1+8*T(v-1))]*[1+sqrt(1+8*T(k))]}/16

T(v-1) is the previous perfect number and T(k) is ONE of the previous, that is to say that k=(1 or 2 or ....or v)

This formula works fine for first 15 perfect numbers but i dont have the knowledge in computer's to test it in biggers perfects.

If the formula is right, then to find the 41 perfect number we have to check only 40 numbers!!!

If anyone has the knowledge in programing to test the formula that will be pretty good!!!

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# A new Perfect number formula

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