1. Sep 9, 2005

### eljose

Let,s suppose we have a particle moving under a potential V:
By Heisenberg picture we know that:

$$\frac{dx}{dt}=p/m$$

so if we knew x(t) and x(t+h) we could calculate the expresion:

$$x(t+\epsilon)-x(t)=p\epsilon/m$$

so knowing x(t) and x(t+e) we could calculate the momentum of the particle:

Last edited: Sep 9, 2005
2. Sep 9, 2005

### seratend

Please do not mix the differential equation between operators and eigenvalues. They are completely different.

Seratend.