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A Physics 11 Elevator Work/Power Problem
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[QUOTE="jasmine_01, post: 6022709, member: 648092"] [h2]Homework Statement [/h2] [B]An elevator takes a 70 kg person from street level to the top of a 400 m sky-scraper in 4 minutes. The mass of the elevator is 500 kg. a] At what rate is the elevator plus the person gaining potential energy? b] What power is the elevator plus the person experiencing as it climbs? c] The motor driving the lift has an efficiency of only 25%. At what rate is the motor working as the lift is going up?[/B][h2]Homework Equations[/h2] How can the elevator calculation be incorporated with the person? How can the efficiency affect the calculation for the work of the motor? [/B][h2]The Attempt at a Solution[/h2] mgh = (70kg)(9.8m/s^2)(400m) Work = Force*Displacement rate of Work = Power Efficiency = Workout/Workin*100% 0.25 * (400m*500kg*9.8m/s^2)/240s Power = Work/Time 4 minutes = 240 s [/QUOTE]
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A Physics 11 Elevator Work/Power Problem
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