52 cards, 13 values (A to K) and 4 suits. what's the probability of getting 5 cards with a four-of-a-kind (same value)?(adsbygoogle = window.adsbygoogle || []).push({});

My solution: first card 52/52, second 3/51, third 2/50. fourth 1/49, fifth 48/48

so (52/52)*(3/51)*(2/50)*(1/49)*(48/48)~4.8e-5

The solution provided by the book 13x48/(C 52 5)~2.4e-4

My solution is 1/5 of the answer. Did I miss something? I think both ways of solving it make sense

Thanks

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# Homework Help: A probability question

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