1. Jan 27, 2017

### garylau

1. The problem statement, all variables and given/known data
A small mass m slides without friction on a surface making a quarter-‐circle with radius R, as shown. Then it lands on the top surface of a cart, mass M, that slides without friction on a horizontal surface. (In practice, this cart could be a slider on an air-‐track.) Between the top of the cart and the mass m, the coefficient of kinetic friction is µk. The mass m slides a distance d along the top of the cart, but doesn't fall off.

(i) When there is no longer any relative motion between m and M, how fast is the cart.Show all working and assumptions and state carefully and explicitly any relevant laws or principles. (Hint: you will find it helpful to break the problem up into seperate stages and to draw diagram for each.

(ii) Determine how far the mass m slides along the surface of the cart before stopping on it. State explicitly any relevant laws or principles and any relevant approximations.

2. Relevant equations

mv1+Mv2=(m+M)v

F=ma 1/2mv^2=mgh
3. The attempt at a solution

i have done the first part successfully and i try to do the second part as following

the correct answer of the (ii) part is : d= {R(M/(m+M)µk}

when i try to use D1-D2 to get the total distance between the cart and the mass
it looks messy

Any other way to do this question?

thank

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Last edited: Jan 27, 2017
2. Jan 27, 2017

### TSny

Your work looks correct. Before subtracting D1 - D2, you might try simplifying D1 to one fraction.

3. Jan 27, 2017

### garylau

thank

but this way looks to complicated

Do you have other method to do this question

thank
for example: do it in the centre of mass frame or using the conservation of energy??

4. Jan 27, 2017

### TSny

It's not that complicated. You've already done most of the work for this method of solving the problem.

Yes, you can approach the problem using energy concepts. It will take less calculation. Was there any loss of mechanical energy from the time block m was released and the time when m and M move together? If so, how much mechanical energy was lost?

5. Jan 27, 2017

### garylau

If i use the centre of mass frame to do this question

Will i got it easily?

6. Jan 27, 2017

### TSny

For me, it seems to take about the same amount of effort to solve it in the CM frame. But I could be overlooking something.

7. Jan 28, 2017

### garylau

using the centre of mass frame

we can let the total final KE =0 because both object moves with the centre of mass

and just find the initial KE ?

8. Jan 28, 2017

### TSny

Yes. Just find the initial KE in the CM frame as m lands on M.