1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

A problem in taking limits

  1. Oct 7, 2011 #1
    This is very basic. I have asked some friends and they dont know. I have tried resolving it by long division, and can see where the 1 comes from but the remainder is 1. I have gone back to the basics, but the operands are multicative. ie 1/a * a = 1
    What is the algebra of this

    The problem in taking limits: Notice that, by division x-2/x-3 = 1 + 1/ x-3.
  2. jcsd
  3. Oct 7, 2011 #2


    User Avatar
    Homework Helper

    What is x approaching on your limit?
  4. Oct 7, 2011 #3


    User Avatar
    Homework Helper
    Education Advisor
    Gold Member

    This is not what you meant:
    You wished to say, [itex]\frac{x-2}{x-3}=1+\frac{1}{x-3}[/itex]

    What does x approach for which you want to find a limit? Is the expression defined at that x value?

    Most likely you are interested in one of these:

    • x approaches negative infinity
      x approaches 0
      x approaches infinity
      x approaches +3
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook