A problem in taking limits

1. Oct 7, 2011

beartopper

This is very basic. I have asked some friends and they dont know. I have tried resolving it by long division, and can see where the 1 comes from but the remainder is 1. I have gone back to the basics, but the operands are multicative. ie 1/a * a = 1
What is the algebra of this

The problem in taking limits: Notice that, by division x-2/x-3 = 1 + 1/ x-3.

2. Oct 7, 2011

gb7nash

What is x approaching on your limit?

3. Oct 7, 2011

symbolipoint

This is not what you meant:
You wished to say, $\frac{x-2}{x-3}=1+\frac{1}{x-3}$

What does x approach for which you want to find a limit? Is the expression defined at that x value?

Most likely you are interested in one of these:

• x approaches negative infinity
x approaches 0
x approaches infinity
x approaches +3