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A problem in taking limits

  1. Oct 7, 2011 #1
    This is very basic. I have asked some friends and they dont know. I have tried resolving it by long division, and can see where the 1 comes from but the remainder is 1. I have gone back to the basics, but the operands are multicative. ie 1/a * a = 1
    What is the algebra of this

    The problem in taking limits: Notice that, by division x-2/x-3 = 1 + 1/ x-3.
  2. jcsd
  3. Oct 7, 2011 #2


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    What is x approaching on your limit?
  4. Oct 7, 2011 #3


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    This is not what you meant:
    You wished to say, [itex]\frac{x-2}{x-3}=1+\frac{1}{x-3}[/itex]

    What does x approach for which you want to find a limit? Is the expression defined at that x value?

    Most likely you are interested in one of these:

    • x approaches negative infinity
      x approaches 0
      x approaches infinity
      x approaches +3
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