How to Find Thrust in Truss Analysis with Hydraulic Rams?

[Eleventh]

Homework Statement

I am required to find the thrust exerted by the hydraulic rams CG and EB. A load of weight 8 kN is placed at F vertically downwards. The system is in mechanical equilibrium. AB = BC = CD = 2m.

Homework Equations

At mechanical equilibrium $$\sum F_x = \sum F_y = \sum M_a = 0$$ (a is any arbitrary point which we take moments about).

The Attempt at a Solution

$$R(\rightarrow ): \ \sum F_x = A_x + G_x = 0$$

$$R(\uparrow ): \ \sum F_y = A_y + G_y - F = 0$$

Resolving clockwise:

$$\ \sum M_A = -80 \times 10^4 - G_y 4 \cos{60^{\circ}} - G_x 4 \sin{60^{\circ}} = 0$$

Though I am not sure how to proceed from here. Any help is appreciated.

EDIT: Nevermind, I have resolved the problem now.

 

[NateD]

G_x = (A_y + F - G_y \cos{60^{\circ}}) / \sin{60^{\circ}}G_y = (A_x + 80 \times 10^4) / \cos{60^{\circ}}Substituting in the above equations,A_x = 4500 NA_y = 6500 NG_x = 12500 NG_y = 6500 N