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A problem

  1. Nov 7, 2004 #1
    if
    Xn = x^n + x^(n-2) + x^(n-4) + ... + 1/[x^(n-4)] + 1/[x^(n-2)] + 1/(x^n)
    (where n is a non-negative integer)

    then ,

    X1 = x + 1/x

    X3 = x^3 + x + 1/x + 1/(x^3)



    What s the value of X2??

    X2 = x^2 + x^0 + 1/(x^2) = x^2 + 1 + 1/(x^2)

    or X2 = x^2 + x^0 + 1/(x^0) + 1/(x^2) = x^2 + 1 + 1 + 1/(x^2)
    ????
     
  2. jcsd
  3. Nov 7, 2004 #2

    Zurtex

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    In your definition you decreased the power of x by 2 each time, so:

    [tex]x2 = x^2 + x^0 + x^{-2} = x^2 + 1 + \frac{1}{x^2}[/tex]

    For [itex]x \neq 0[/itex]
     
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