A cannon fires successively two shells with velocity u=250 m/s;the first at angle [tex]\theta1[/tex]=[tex]\pi/3[/tex] & the second shell at an angle [tex]\theta2[/tex]=[tex]\pi/4[/tex] to the horizontal, the azimuth being same. Neglecting air drag, find the time interval between firings leading to colling of shells.
Time of flight t=(2usin[tex]\theta[/tex])/g
The Attempt at a Solution
I'm really confused &unable to figure out.
Book says that its 11s.