a projectile of mass of .787 kg is shot from a cannon, at height 6.8 m as shown in the figure with an initial velocity vi having a horizontal component of 5.7m/s2. vix cos53 5.7=.6018150232 9.471348804=vi viy=sin53 * vi viy=.79863551*9.471348804 viy=7.564155483 Determine the MAximum height deltay the projectile achieves after leaving the end of the cannon's barrel. answer in units of m/s. a=9.8 vi=7.564155483 vf=0 vf^2=vi^2 +2as 0=(7.564155483)^2 +2(9.8)s 57.21644817+19.6s -57.21644817=19.65 s=2.919206539 HELP!!! Find the magnitude of the velocity vector when the projectile hits the ground. Answer in units of m/s. Find the magnitude of the angle (with respect to horizontal0 the projectile makes when im pacting the ground. Answer in units of degrees.