1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: A proton has a speed of 3 x 10^6 m/s

  1. May 28, 2003 #1


    User Avatar

    I need help deriving a formula to solve for this please.

    A proton has a speed of 3 x 10^6 m/s in a direction perpendicular to a uniform magnetic field and the proton moves in a circle radius .2 m. what is the magnitude of the magnetic field?

    If someone can show me the all formulas to use i can manipulate from here.
    Dx :wink:
    Last edited by a moderator: Feb 5, 2013
  2. jcsd
  3. May 28, 2003 #2


    User Avatar
    Science Advisor

    A particle with mass m, charge q, moving at speed v in a constant magnetic field of magnitude B at right angles to the velocity vector of the particle, will move in a circle with radius mv/(qB)
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook