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**1. Homework Statement**

Two masses, M1= 35.0 kg and M2= 38.0 kg, are connected by a rope that hangs over a pulley. The pulley is a uniform cylinder of radius 0.381 m and mass 3.5 kg. Initially M1 is on the ground and rests 2.5 m above the ground. If the system is released, use conservation of energy to determine the speed of just before it strikes the ground. Assume the pulley bearing is frictionless.

**2. Homework Equations**

F= m*a Torque= r x F

**3. The Attempt at a Solution**

I found the tension that M2-M1 put on the pulley.

F=(38.0-35.0)*9.8= 29.4

I'm a little lost after that. How do I find the speed of the pulley?