- #26

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With ##\phi = 0##, the probability of getting opposite spins is:Got it. But if we limit ourselves to a plane (which I was assuming as its in the video example hence the confusion) we can set ##\phi##=0 in #21 then from it we can get the probability of opposite spin. But, it doesn't answer about the probability of ##\uparrow \uparrow## and ##\downarrow \downarrow## each given arbitrary α, β.

PS Sorry for testing your patience.

$$\frac 1 2 |\alpha - \beta|^2 \sin^2 \theta $$