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A question about analysis

  1. Dec 1, 2012 #1
    Show that [tex] \int_0^1 x^{-p} dx = \frac{1}{1-p}[/tex] if 0<p<1 and [tex] \int_0^1 x^{-p} dx = +\inf[/tex] if p>1. Can anybody please give me a hint?

    Thanks in advance
  2. jcsd
  3. Dec 1, 2012 #2
    Hints: Fundamental Theorem of Calculus, Improper integrals
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