A question about GUTS

  • Thread starter Jim Kata
  • Start date
  • #1
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Main Question or Discussion Point

I don't have access to Georgi's and Wilcheck's work, if somebody has some good links to an overview of the su(5), so(10), and e6 GUTS that would be awesome.

Anyways, there's something I really don't get, lets take su(5) for example, su(5) has the root system [tex]A_4[/tex] now there is 4(4+2) = 24 generators of the lie algebra. Now I know they didn't use all 24 of the generators because it would mean that there were 24 gauge bosons, not including the Higgs. So I heard they used a diagonal representation of su(5). Something like

[su(3)0]
[0 su(2)]

Does that entail just using the Cartan subalgebra or what? What did they do?
 

Answers and Replies

  • #2
Avodyne
Science Advisor
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All 24 gauge bosons are there, but SU(5) is spontaneously broken to SU(3)xSU(2)xU(1) by a vacuum expectation value for a Higgs fields in the adjoint representation.

Srednicki's QFT book (available free on his website) has a good basic discussion of the SU(5) model.
 
  • #3
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I don't have access to Georgi's and Wilcheck's work, if somebody has some good links to an overview of the su(5), so(10), and e6 GUTS that would be awesome.

Anyways, there's something I really don't get, lets take su(5) for example, su(5) has the root system [tex]A_4[/tex] now there is 4(4+2) = 24 generators of the lie algebra. Now I know they didn't use all 24 of the generators because it would mean that there were 24 gauge bosons, not including the Higgs. So I heard they used a diagonal representation of su(5). Something like

[su(3)0]
[0 su(2)]

Does that entail just using the Cartan subalgebra or what? What did they do?
I'm not at all a specialist of GUT, but I think only generators from SU3 x SU2 x U1 are diagonal and commute. Other generators are non-diagonal and entail the breaking of SU5 into SU3 x SU2 x U1.
If you have good www ressources, I'm also interested.
 

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