Let be the Kelin-gordon equation (m=0) with a potential so:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] (-\frac{\partial ^{2}}{\partial t^{2}}+V(x) )\Phi=0 [/tex]

my question is if you consider the wave function above as an operator..is the K-G operator of the form:

[tex] <0|T(\Phi(x)\Phi(x')|0> [/tex] T=time ordered

I think that in both cases..we use the same wave function but once is an scalar (or an spinor for electrons) and the other is an escalar...:shy: :shy:

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# A question about operators

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