- #1

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i tried everything all i figerd out is that they r displacmednts the accelaration is 9.8 and nothing i dont have enogh info to do anything

plz help me

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- Thread starter ouse
- Start date

- #1

- 33

- 0

i tried everything all i figerd out is that they r displacmednts the accelaration is 9.8 and nothing i dont have enogh info to do anything

plz help me

- #2

Päällikkö

Homework Helper

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- #3

- 33

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can u plz elaborate

- #4

- 33

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and any way that dosnt work becuse i have no angles to detrime wat the x and y componants are

- #5

- 33

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that would only work if these were vectors not displacment

- #6

Päällikkö

Homework Helper

- 519

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Well...

[tex]x = v_0t[/tex]

[tex]0 = y_0 -\frac{1}{2}gt^2[/tex]

Does that help at all?

[tex]x = v_0t[/tex]

[tex]0 = y_0 -\frac{1}{2}gt^2[/tex]

Does that help at all?

- #7

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yeah it helped i acctualy figerd the question thx sooo much

- #8

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now can u plz look at my other thread and plz ohh plz help with question 1 b,c and q 2

- #9

Päällikkö

Homework Helper

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Glad to hear that :).ouse said:yeah it helped i acctualy figerd the question thx sooo much

Did you understand where the equations I gave came from?

- #10

- 33

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ummm well yeah for one of them

- #11

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u assumed viy is 0 and took it our of the equation right

- #12

Päällikkö

Homework Helper

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[tex]x = x_0 + v_{x0}t + \frac{1}{2}a_xt^2[/tex]

[tex]y = y_0 + v_{y0}t + \frac{1}{2}a_yt^2[/tex]

Let [itex]x_0 = 0[/itex]. As the projectile's fired horizontally: [itex]v_{y0} = 0[/itex] thus [itex]v_{x0} = v_0[/itex]. No force affects the projectile in x-direction, so: [itex]a_x = 0[/itex]. In y-direction: [itex]a_y = -g[/itex] (- as it's downward). The final altitude of the projectile is [itex]y = 0[/itex].

Hence

[tex]x = v_0t[/tex]

[tex]0 = y_0 -\frac{1}{2}gt^2[/tex]

- #13

- 33

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- #14

- 33

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thx for the explination

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