Hi guys, here's the question.(adsbygoogle = window.adsbygoogle || []).push({});

A string, which has linear density [tex] \mu [/tex], is suspended vertically. Someone produces a wave from the bottom of the string. Please prove that the wave is moving with constant acceleration

My solution:

let x be the distance between a point on the string and the bottom of the string then

[tex] T= \mu x g [/tex] where T is tension

so

[tex] v= \sqrt{ \frac{T}{\mu} } = \sqrt {gx} [/tex]

then

[tex] a= \frac{dv}{dt} = \frac{dv}{dx} \frac{dx}{dt} = \frac{1}{2} g [/tex]

Am I right or wrong? I'm not sure this really works.

Could someone sovle this problem by other mathematical approach, and tell me why the wave move with constant accleration qualitatively?

Thanks in advanced!

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# A question of wave

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