A question on enantiomeric excess

  • Thread starter biochemist
  • Start date
In summary, a racemic mixture of 98:2 enantiomers consists of one enantiomer in 96% over the other due to the assumption that the (+) enantiomer is predominant. The other enantiomer does not have a negative percentage value of enantiomeric excess because it is not in excess, but rather shades out an equal percentage of the predominant enantiomer. This means that if you have 98%(+) and 2%(-), the 2%(-) will shade out an equal amount of the (+) enantiomer, leaving 96%(+) of pure enantiomer.
  • #1
biochemist
11
0
Why does a racemic mixture of 98:2 enantiomers consist of one enantiomer in 96% over the other? I'm still not clear about this after reading textbooks. And how about the other one? does it have a negative percentage value of enantiomeric excess?
 
Chemistry news on Phys.org
  • #2
ee = %(+) - %(-) assuming the (+) enantiomer is predominant.

also, there is no excess of the (-) enantiomer because there is only an excess of the (+) enantiomer (see the assumption above).

just think of it as if the lesser enantiomer shades out an equal percentage of the predominant enantiomer. so if you have 98%(+) and 2%(-), 2%(-) will shade out 2%(+) and you're left with 96%(+) pure enantiomer. i don't know if that makes sense, but i hope it helps :smile:.
 
  • #3


The reason for this is due to the concept of enantiomeric excess. Enantiomeric excess (EE) is a measure of the difference in the amount of two enantiomers present in a mixture. It is calculated using the formula: (moles of desired enantiomer - moles of undesired enantiomer) / total moles in the mixture.

In the case of a racemic mixture, the moles of each enantiomer are equal, resulting in an EE of 0%. However, when one enantiomer is present in a higher amount (98%) compared to the other (2%), the EE is calculated as follows: (0.98 - 0.02) / 1 = 0.96 or 96%. This means that the desired enantiomer is present in excess of 96%, while the undesired enantiomer is present in the remaining 4%.

As for the other enantiomer, its EE would be calculated as: (0.02 - 0.98) / 1 = -0.96 or -96%. This indicates that the undesired enantiomer is present in excess of 96%, while the desired enantiomer is present in the remaining 4%.

It is important to note that the EE of one enantiomer is always the inverse of the other. In the case of a racemic mixture, both enantiomers have an EE of 0%, while in a mixture with a higher amount of one enantiomer, the EE of that enantiomer will be a positive value and the EE of the other enantiomer will be a negative value.

I hope this helps to clarify the concept of enantiomeric excess for you. It is a crucial concept in understanding the composition of chiral mixtures and how to analyze and separate them.
 

1. What is enantiomeric excess?

Enantiomeric excess (ee) is a measure of the difference in amounts of two enantiomers (mirror-image molecules) present in a sample. It is expressed as a percentage and indicates which enantiomer is present in greater quantity.

2. Why is enantiomeric excess important?

Enantiomeric excess is important because it can affect the properties and behavior of a substance. For example, one enantiomer of a drug may be more effective or have different side effects than the other. It is also important in the production of chiral compounds, where having a high ee is desired for optimal results.

3. How is enantiomeric excess determined?

There are various methods for determining enantiomeric excess, including polarimetry, chiral chromatography, and NMR spectroscopy. These techniques involve comparing the optical rotation, retention time, or chemical shifts of the enantiomers in a sample.

4. What factors can affect enantiomeric excess?

The ee of a substance can be affected by various factors, such as the starting materials used in its synthesis, the reaction conditions, and the presence of chiral catalysts. It can also be influenced by external factors such as temperature and solvent choice.

5. Can enantiomeric excess be changed?

Yes, enantiomeric excess can be changed through various methods, such as using different reaction conditions, altering the ratio of starting materials, or using different chiral catalysts. However, the ee of a substance is determined by its molecular structure and cannot be changed once the substance is formed.

Similar threads

Replies
2
Views
2K
  • Chemistry
Replies
4
Views
14K
  • General Math
Replies
2
Views
879
Replies
2
Views
4K
Replies
4
Views
4K
Replies
4
Views
21K
  • Atomic and Condensed Matter
Replies
8
Views
1K
Replies
4
Views
3K
  • Atomic and Condensed Matter
Replies
6
Views
1K
Replies
3
Views
997
Back
Top