- #1

- 96

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My answer is this:

Consider the following linear map:

T|u>=|u> if |u> belongs to V-U and T|u>=|0> if |u> belongs to U

Therefore kerT=U

Is this correct?

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- Thread starter kostas230
- Start date

- #1

- 96

- 3

My answer is this:

Consider the following linear map:

T|u>=|u> if |u> belongs to V-U and T|u>=|0> if |u> belongs to U

Therefore kerT=U

Is this correct?

- #2

tiny-tim

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Consider the following linear map:

T|u>=|u> if |u> belongs to V-U and T|u>=|0> if |u> belongs to U

Therefore kerT=U

Is this correct?

nooo …

i] that's a map from V to V, not to W

ii] what do you mean by V-U ? (eg what is R

- #3

- 96

- 3

i] that's a map from V to V, not to W

Silly me, I overlooked it xD

ii] what do you mean by V-U ? (eg what is R^{3}- R^{2}?)

I mean the elements of V that do not belong in U.

- #4

tiny-tim

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I mean the elements of V that do not belong in U.

then R

- #5

- 96

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Complement (set theory) - Wikipedia, the free encyclopedia

- #6

tiny-tim

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Well, the correct answer would be: ℝ^3-ℝ^2={(0,0,z):z is real

that's a line

add a line to R

- #7

HallsofIvy

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R

I think you need to review your definitions!

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