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A question on norton method

  1. May 15, 2008 #1
    why "I" is negative??

    http://img391.imageshack.us/my.php?image=img8855ew6.jpg

    i know that KCL says that the sum of the currents that goes in
    equals the sum of the currents that goes out

    here i dont know what current goes into the node
    and what current goes out??
     
  2. jcsd
  3. May 15, 2008 #2
    current in = current out
    I (current into node) = (e-v)/R1 + e/R2 (current out of node)
     
  4. May 15, 2008 #3
    i dont know how you decided the direction of each current

    i am new to this stuff
    and i think that the "I" current is pointed up
    so it goes into the node
    the second current the goes threw "R1" also come into the node
    because the currect goes from the plus of the battery to minus of the battery

    where did i go wrong
     
  5. May 15, 2008 #4
    you can make current go any way you want as long as you stick to the same convention throughout the circuit (this is just something to keep in mind)

    In this case, you have 3 lines in your circuit with respect to that node. Current is not pointing up. That is just a symbol for current. It says current is flowing in that line going that direction. It is going 'into' the node. What goes in must come out equally. If it goes in 1A, it has to come out 1A.

    Now, if you want to make current at R1 going into the node, you can do it too but then the convention changes.
    ie:
    going in = going out
    I + (v-e)/R1 = e/R2
    e/R2 - I -(v-e)/R1 = 0
    e/r2 -I +(e-v)/R1 = 0

    Observe the sign symbol; -(v-e) = e-v
    see how it comes back the same? When current flows one way, then your I is the voltage differential (from) - (to). If you made R1 current 'going into', it will be (v-e)/r1. If you made R1 current 'going out' from node, it will be (e-v)/R1.

    Hope this helps
     
  6. May 15, 2008 #5
    what conventions???

    i cant see how the currents flow using these conventions

    in what case we have e-v and in what v-e
    ???
     
  7. May 15, 2008 #6
    delete

    It would be best if you draw a simple circuit, with voltage and 1 resistor. What is the current? What happens if you add 2 resistor in series now. What is the current and voltage between both resistor. Keep adding, another resistor in parallel with 2 resistor in series and find current/voltage ...etc

    Try this site
    Read thru it
    http://www.allaboutcircuits.com/vol_1/chpt_6/4.html. Take a look at ohms law, simple current and voltage rules.
     
    Last edited: May 15, 2008
  8. May 15, 2008 #7
    i know ohm laws

    but here i cant construct them
    because of these new symbols
    they differ the normal symbols
     
  9. May 15, 2008 #8

    berkeman

    User Avatar

    Staff: Mentor

    I'm not sure I understand your confusion. The symbol on the right is a current source. The arrow on the symbol shows which way the current is flowing through the current source. The "up" arrow means that the current is being pumped up from ground and into the top node.

    The equation the way you have written it is summing all of the currents flowing *out* of that node, so the current from the current source leg of the circuit is marked as negative.
     
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