Calculate PPM of *Fluoride* in standard solution. NaF (dissolved in solution) = 1.0534g in 0.250L distilled water.
PPM = Mol/L * g/mol * 1000
The Attempt at a Solution
C=n/V, n = m/M
n = 1.0534/41.99 = 0.02509
c = n/V = 0.02509/0.250 = 0.1M
PPM = 0.1M * 41.99g/mol * 1000 = 4213.59PPM
BUT! Sure that's the PPM of NaF in the solution, but to get the PPM of FLUORIDE do I need to divide it by 2? (NaF, 1:1 ratio) or do I use the mW of F in the PPM equation? (19 instead of 41.99)?
Thanks for any help.