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A quick question on logarithms

  1. Sep 6, 2007 #1
    I've been working on logarithms in my calculus class and I came acrossed one with a square root. Since I am new to these types of problems I'm not sure how to work with this yet.

    How would I solve something such as loge[square root of e]
     
  2. jcsd
  3. Sep 6, 2007 #2
    Welcome to PF, Antisubs12.

    Do you know another (equivalent) way to write

    [tex]\log_{a}x^y = ?[/tex]
     
  4. Sep 6, 2007 #3

    cristo

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    Well, [itex]\ln\sqrt{e}=\ln e^{1/2}=\frac{1}{2}\ln{e}=\frac{1}{2}[/itex]. Where the second equality comes from the rule ln(a)^b=b ln(a)
     
  5. Sep 6, 2007 #4
    how would you write square root of e in expediential form? After you do that ask your self what law of logs will help you make the problem more workable.
     
  6. Sep 6, 2007 #5
    ah thanks, i had forgotten there was a way to write square roots in exponential form. I can handle things from here. Thanks again.
     
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