I tried to get a_rad and if i didn't make any mistake, then a_rad = 15.79 m/s. I need to find angle when the bean is at vertical equilibrium.
a_rad= v^2/R = 4(pi)^2R/T^2
The Attempt at a Solution
v= 2(pi)R/0.25 sec = .2pi/0.25= .89m/sec
a_rad= 4pi^2(0.1)/.25= 15.79 m/s^2
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