A rather simple DE problem

1. Jan 6, 2007

Dr Game

1. The problem statement, all variables and given/known data

Verify that the function is a solution of the DE

$$Dy = \frac{2y}{x} , y = Cx^2$$

2. The attempt at a solution

$$LHS = Dy = D(Cx^2) = 2 Cx$$
$$RHS = \frac{2y}{x}$$

then... I really don't know what to do from there... do I just simply things?

2. Jan 6, 2007

HallsofIvy

Staff Emeritus
Well, how about replacing that y in RHS with Cx2?

3. Jan 6, 2007

Dr Game

$$2Cx = \frac {2Cx^2}{x}$$

$$2Cx = 2Cx$$

is that possible?

4. Jan 6, 2007

SunGod87

Yes, that's fine.