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A rather simple DE problem

  1. Jan 6, 2007 #1
    1. The problem statement, all variables and given/known data

    Verify that the function is a solution of the DE

    [tex]Dy = \frac{2y}{x} , y = Cx^2[/tex]

    2. The attempt at a solution

    [tex]LHS = Dy = D(Cx^2) = 2 Cx[/tex]
    [tex]RHS = \frac{2y}{x}[/tex]

    then... I really don't know what to do from there... do I just simply things?
  2. jcsd
  3. Jan 6, 2007 #2


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    Staff Emeritus
    Science Advisor

    Well, how about replacing that y in RHS with Cx2?
  4. Jan 6, 2007 #3
    [tex]2Cx = \frac {2Cx^2}{x}[/tex]

    [tex]2Cx = 2Cx[/tex]

    is that possible?
  5. Jan 6, 2007 #4
    Yes, that's fine. :smile:
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