(adsbygoogle = window.adsbygoogle || []).push({}); A real challenge to all physicsist!!!

In order to experience free fall a student walks off the top of the CN Tower which is 553m high and falls freely. His initial velocity is zero. The rocketeer arrives at the scene 5 seconds later and dives off the top of the tower to save the student. The rocketeer leaves the roof with an initial downward speed v_{0}. in order both to get the student and to prevent injury to him the rocketeer should catch the student at a sufficiently great height above ground so that the rocketeer and the student slow down and arrive at the ground with zero velocity. The upward acceleration that accomplish this is provided by the rocketeer's jet pack. which is turned on just as he catch the student. Before then the rocketeer is in free fall. To prevent discomfort to the student the magnitude of the acceleration of rocketeer and the student as they move downward together should be no more that 5 times g. What is the minimum height above the ground at which the rocketeer should catch the student? What must be the rocketeer's initial downward speed so that he catch the student at the minimum height found above.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: A real challenge to all physicsist

**Physics Forums | Science Articles, Homework Help, Discussion**