A real challenge to all physicsist

  • #1
Ali Asadullah
99
0
A real challenge to all physicsist!!!

In order to experience free fall a student walks off the top of the CN Tower which is 553m high and falls freely. His initial velocity is zero. The rocketeer arrives at the scene 5 seconds later and dives off the top of the tower to save the student. The rocketeer leaves the roof with an initial downward speed v0. in order both to get the student and to prevent injury to him the rocketeer should catch the student at a sufficiently great height above ground so that the rocketeer and the student slow down and arrive at the ground with zero velocity. The upward acceleration that accomplish this is provided by the rocketeer's jet pack. which is turned on just as he catch the student. Before then the rocketeer is in free fall. To prevent discomfort to the student the magnitude of the acceleration of rocketeer and the student as they move downward together should be no more that 5 times g. What is the minimum height above the ground at which the rocketeer should catch the student? What must be the rocketeer's initial downward speed so that he catch the student at the minimum height found above.
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,836
255
Hi Ali! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

Suggested for: A real challenge to all physicsist

  • Last Post
Replies
7
Views
2K
  • Last Post
Replies
8
Views
8K
Replies
0
Views
2K
Replies
0
Views
968
Replies
2
Views
6K
  • Last Post
Replies
1
Views
1K
Replies
10
Views
2K
  • Last Post
Replies
7
Views
664
Replies
0
Views
2K
Replies
2
Views
2K
Top