(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

For 6.5 s, a rocket rises in a straight line oriented at 70° from the horizontal axis with a constant acceleration module of 8m/s^{2}. Then she is goes into free fall.

Find:

a) the maximum height

b) its horizontal reach

2. Relevant equations

t = ( v_{fv}- v_{iv})/a

d = v_{ih}t + (0.5)at^{2}

I believe?

y= y_{i}+ v_{yo}t -(0.5)gt^{2}

x= v_{xo}t

3. The attempt at a solution

so ive got these given infos:

t= 6,5

x_{i}= 0

x_{f}= ?

y_{i}= 0

y_{f}= ?

a= 8 m/s^{2}

a) to find y_{f}at v_{f}=0

y= v_{o}(sin(70))t -(0,5)(9,8)t^{2}

But then, i wonder if i should replace gravity with acceleration, but seeing as were working with y, doesnt that mean i HAVE to use -9,8 as my g (or a) value? From what i understand, I only use 8m/s^{2}when i have to calculate wth the values of x? I'm confused. Someone explain that at least! I have a strong feeling im heading in the wrong direction with my work so far. Boost me?

b) as for this one, im guessing i have to find x_{f}after 6,8 seconds once i find the value of v_{0}, I'm guessing things will fall into place. But do correct me if im wrong?

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# A rocket rises straight at a 70 degree angle then falls.using its acceleration,find

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