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A seagull and clams

  1. Oct 14, 2009 #1
    1. A seagull diving towards a stone beach at an angle of 60 degrees to the vertical releases a clam from a height of 100 meters. The clam hits the beach 3.32 seconds later. To the nearest tenth of a m/s what was its speed when it was released?



    2. v=v_0 + a*t
     
  2. jcsd
  3. Oct 14, 2009 #2

    rl.bhat

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    Homework Helper

    If v is the velocity of seagull when it releases the clam, find the horizontal and vertical components of v.
    Height is given, time is given and g is known.
    Use the proper kinematic equation to find vy.
    From that you can find vx.
    required answer is vx*t.
     
  4. Oct 14, 2009 #3
    Thanks, I think that I got it now
     
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