Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: A 'simple' projectile problem.

  1. Sep 20, 2005 #1
    This problem has been giving me headaches for the past two weeks. Here it is, as well as how far I have gotten on it:

    A projectile is fired with an initial velocity of 53m/s. Find the angle of projection such that the maximum height is equal to it's range.

    So that basically boils down to:

    H = R
    Vo = 53m/s
    ay = -9.81m/s^2
    t = unknown
    x (angle) = find

    According to the nifty sheet the teacher tossed out the applicable formulas would be:

    R=Vo^2*sin(2x)/g (since Ho and Hf will be the same)
    H=Voy^2/2g.

    Making H=R gets the formula Voy^2=2*Vo^2*sin(2x) ...which doesn't help me since x is what needs to be found, and without x one can't break Vo into component form.

    Do I have the right idea or have I flubbed it already?

    Thanks,

    -K
     
  2. jcsd
  3. Sep 20, 2005 #2
    Voy=vo*sinx
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook