This problem has been giving me headaches for the past two weeks. Here it is, as well as how far I have gotten on it:(adsbygoogle = window.adsbygoogle || []).push({});

A projectile is fired with an initial velocity of 53m/s. Find the angle of projection such that the maximum height is equal to it's range.

So that basically boils down to:

H = R

Vo = 53m/s

ay = -9.81m/s^2

t = unknown

x (angle) = find

According to the nifty sheet the teacher tossed out the applicable formulas would be:

R=Vo^2*sin(2x)/g (since Ho and Hf will be the same)

H=Voy^2/2g.

Making H=R gets the formula Voy^2=2*Vo^2*sin(2x) ...which doesn't help me since x is what needs to be found, and without x one can't break Vo into component form.

Do I have the right idea or have I flubbed it already?

Thanks,

-K

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# A 'simple' projectile problem.

**Physics Forums | Science Articles, Homework Help, Discussion**