A simple question but i don't get it

  • Thread starter Tensaiga
  • Start date
In summary, the quarterback must throw the football at an angle of approximately 18 degrees, relative to the sidelines, in order to hit the open receiver. The receiver is approximately 23 meters downfield from the quarterback. The correct calculation for the angle is tan = 2.5/8 and the velocity of the ball relative to the ground is 17.35 degrees. Using the Pythagorean Theorem, the total distance traveled by the ball is approximately 22.80 meters.
  • #1
Tensaiga
43
0
Hello, there's my question.

A quarterback is running across the field, parallel to the line of scrimmage, at a constant speed of 2.5m/s, when he spots an open, stationary receiver straight downfield from him (ie, in a line parallel to the sidelines). If he can throw the football at a speed of 8.0m/s, relative to himself, at what angle, relative to the sidelines, must he throw it in order to hit the receiver? How far downfield was the receiver

I drew a diagram but i got 72 degress and 25m as the answer... but the correct answer should be 18 degrees and 23m. where did i go wrong?

i used tan = 8/2.5 and used that answer mutiplied by the velocity.

Thanks

Sorry i posted in the wrong place, just saw the head lines now...
 
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  • #2
Show us your work.

Hint: What is the velocity of the ball relative to the (static) ground.
 
  • #3
oh never mind i get it now = =

it's suppose to be Tan angle = 2.5/8
= 17.35 degrees

then C^2 = A^2 + B^2
= 22.80m
thanks~
 

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