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Block 1 as shown in the link below(url) has a mass of 10.3 kg. The coefficient of static friction between the block and the table is μs = 0.36 and the coefficient of kinetic friction is μk = 0.336.

a) What should the mass of the second block be so that m1 is just on the verge of sliding?

I ended up getting (10.3 kg)*(0.36) , which was correct

b) If the block 2 has the mass you just calculated above, what is the tension in the string?

I got (10.3*0.36)(9.81), and that was also correct

c) If the block 2 has the mass you just calculated above and then block 1 is given a slight nudge, what is the tension in the string?

So i did the FBD, to solve for acceleration of the blocks, and i got ((M2 - Uk*M1)/(M1+M2)) *g = a

i plugged acceleration back into this equation Ft = m1*a + Ffric => where Ffric is (Uk*m1*g)

and that was not correct please help me

here's the pic

https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2111/fall/homework/Ch-06-Forces/tipler_sliding_block/fig_05_10.jpg [Broken]

a) What should the mass of the second block be so that m1 is just on the verge of sliding?

I ended up getting (10.3 kg)*(0.36) , which was correct

b) If the block 2 has the mass you just calculated above, what is the tension in the string?

I got (10.3*0.36)(9.81), and that was also correct

c) If the block 2 has the mass you just calculated above and then block 1 is given a slight nudge, what is the tension in the string?

So i did the FBD, to solve for acceleration of the blocks, and i got ((M2 - Uk*M1)/(M1+M2)) *g = a

i plugged acceleration back into this equation Ft = m1*a + Ffric => where Ffric is (Uk*m1*g)

and that was not correct please help me

here's the pic

https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2111/fall/homework/Ch-06-Forces/tipler_sliding_block/fig_05_10.jpg [Broken]

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