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A sound problem

  1. Mar 10, 2006 #1
    i need some help with this question.

    "Jim is walking in a field and screams...the wall is 300 meters away it takes 1.7 seconds for the sound to come back.......wat is the temperature in the air."

    so i tried it as:

    ....= 300m/0.85s
    ....= 353m/s

    from there i think i have to use the speed of sound formula and isolate the 0.59t. and then divide by it. i keep on getting a different answer then the one in my textbook.
  2. jcsd
  3. Mar 10, 2006 #2
    Cair= 331.5 + (0.6 x theta)
    353 = 331.5 + (0.6 x theta)
    theta = (353 - 331.5)/0.6
    theta = 35.8 ºC

    It's hot!
    Notice that I get this formula from wikipedia, I could be wrong since I never learned this. But I read the article and it seems to be correct.

    See- http://en.wikipedia.org/wiki/Speed_of_sound
  4. Mar 10, 2006 #3
    thanks its correct...
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